de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

1/(1+y^2)y^'=x

Lösung

\frac{1}{1 + y ^{2}} y^{^{'}} = x

Lösung

y = tan (\frac{x ^{2}}{2} + c_{1})

Schritte zur Lösung

\frac{1}{1 + y ^{2}} y^{'} (x) = x

Solve separable ODE:

y = tan (\frac{x ^{2}}{2} + c_{1})

y = tan (\frac{x ^{2}}{2} + c_{1})

Graph

Beliebte Beispiele

y^'+2yt=0,y(1)=((e+3))/2

y^{^{'}} + 2 y t = 0, y (1) = \frac{( e + 3 )}{2}

(dy)/(dx)=14e^{5x-4y}

\frac{d y}{d x} = 14 e^{5 x - 4 y}

e^x3yy^'=e^{-y}+e^{-4x-y}

e^{x} 3 y y^{^{'}} = e^{- y} + e^{- 4 x - y}

y^'=(9x)/(y+x^2y),y(0)=-7

y^{^{'}} = \frac{9 x}{y + x ^{2} y}, y (0) = - 7

(dy)/(dx)=-4/7 x^3y^3

\frac{d y}{d x} = - \frac{4}{7} x^{3} y^{3}