y^'y^2x=y^3

Lösung

y^{^{'}} y^{2} x = y^{3}

y = c_{1} x

Schritte zur Lösung

y^{'} (x) y^{2} x = y^{3}

Solve separable ODE:

y = c_{1} x

y = c_{1} x

2 + y^{^{'}} = 6 y, y (- 2) = 8

y^{^{'}} y = (4 x^{3} + 5) (4 x^{7} - 7)

4 (5 x - 3)^{2} \frac{d y}{d x} = 2 y - 4

\frac{d y}{d x} = \frac{2 ( 5 - y )}{x}

x y^{3} d x - (y + 1) e^{- x} d y = 0