y^'+((10^3))/4 y-2*10^3=0

Lösung

y^{^{'}} + \frac{( 1 0 ^{3} )}{4} y - 2 \cdot 1 0^{3} = 0

y = e^{- 250 t - c_{1}} + 8

Schritte zur Lösung

y^{'} (t) + \frac{( 1 0 ^{3} )}{4} y - 2 \cdot 1 0^{3} = 0

Solve separable ODE:

y = e^{- 250 t - c_{1}} + 8

y = e^{- 250 t - c_{1}} + 8

\frac{d y}{d x} x^{6} y + 8 = y + 7

\frac{d y}{d x} = 6 x^{5} y

2 x y^{^{'}} + y = 0

y y^{^{'}} = 4 x + 9

\frac{df}{d t} f (t) = (sin (t^{2}) + 1)^{4}