y^'=(cot^2(x))/(2y)

Lösung

y^{^{'}} = \frac{cot ^{2} ( x )}{2 y}

y = - x - cot (x) + c_{1}, y = - - x - cot (x) + c_{1}

Schritte zur Lösung

y^{'} (x) = \frac{cot ^{2} ( x )}{2 y}

Solve separable ODE:

y = - x - cot (x) + c_{1}, y = - - x - cot (x) + c_{1}

y = - x - cot (x) + c_{1}, y = - - x - cot (x) + c_{1}

\frac{d z}{d t} = 8 t e^{3 z}

y^{^{'}} + y = 40

x^{^{'}} = 1 - x

\frac{d y}{d t} = 0.06 - \frac{y}{948}

\frac{d y}{d x} = y^{3}, y (0) = 1