y^'=y*cot(x)

解答

y^{^{'}} = y \cdot cot (x)

y = c_{1} sin (x)

求解步骤

y^{'} (x) = y \cdot cot (x)

求解可分离方程:

y = c_{1} sin (x)

y = c_{1} sin (x)

- x^{^{'}} = b x

y^{^{'}} = 2 \frac{x}{( y + x ^{2} y )}, y (0) = - 2

\frac{d y}{d x} y = x^{4 x}

\frac{d y}{d x} y = cosh^{2} (3 x) - sinh (x^{2})

\frac{d y}{d x} = \frac{3 + 12 x}{x y ^{2}}, x > 0