y^'+4ty=-2t

Lösung

y^{^{'}} + 4 t y = - 2 t

y = \frac{e ^{- 2 t^{2} + c_{1}}}{2} - \frac{1}{2}

Schritte zur Lösung

y^{'} (t) + 4 t y = - 2 t

Solve separable ODE:

y = \frac{e ^{- 2 t^{2} + c_{1}}}{2} - \frac{1}{2}

y = \frac{e ^{- 2 t^{2} + c_{1}}}{2} - \frac{1}{2}

x y^{^{'}} - y = 4 x^{9} y, y (1) = 10

y^{^{'}} = \frac{x ^{2} - 7}{y ^{2}}, y (0) = 4

x^{^{'}} = \frac{1}{x ^{3} - x}, x (0) = - 2

\frac{d y}{d x} = y^{4} cos (x)

\frac{d r}{d t} = 4 r t