y^'=(1/(1+x))y

Lösung

y^{^{'}} = (\frac{1}{1 + x}) y

y = e^{c_{1}} + e^{c_{1}} x

Schritte zur Lösung

y^{'} (x) = (\frac{1}{1 + x}) y

Solve separable ODE:

y = e^{c_{1}} + e^{c_{1}} x

y = e^{c_{1}} + e^{c_{1}} x

6 x - 4 y x^{2} + 1 \frac{d y}{d x} = 0, y (0) = - 5

6 u z^{2} d u = u d z

y^{^{'}} = 4 y + b, y (0) = 1

\frac{d v}{d t} = 3 \frac{2}{9} v

a x^{^{'}} + x = 0