(dP)/(dt)=a*P

Lösung

\frac{d P}{d t} = a \cdot P

P = e^{a t + c_{1}}

Schritte zur Lösung

\frac{d P}{d t} = a \cdot P

Solve separable ODE:

P = e^{a t + c_{1}}

P = e^{a t + c_{1}}

x^{^{'}} = x^{2} (t^{2} - 1) (t^{2} - 9), x (0) = 1

\frac{d y}{d x} + y = y^{- 2}

2 d y - (y - 7)^{2} d x = 0

\frac{d}{d x} (y^{3}) = 50 x

\frac{d y}{d x} = \frac{1}{y - 2}