y^'=8t-10t-2t*y

Lösung

y^{^{'}} = 8 t - 10 t - 2 t \cdot y

y = e^{- t^{2} + c_{1}} - 1

Schritte zur Lösung

y^{'} (t) = 8 t - 10 t - 2 t \cdot y

Solve separable ODE:

y = e^{- t^{2} + c_{1}} - 1

y = e^{- t^{2} + c_{1}} - 1

\frac{d}{d x} (x y) = cot (x) y

y^{^{'}} - e^{y} x = 0

x \cdot \frac{d y}{d x} = \frac{1}{y ^{3}}

y^{^{'}} = x^{6} y^{- 5}

\frac{d y}{d x} = 3 x (1 + y^{2})