(xy+x)dx+(yx+y)dy=0

Lösung

(x y + x) d x + (y x + y) d y = 0

y = - W (- \frac{1}{e ^{- x + c_{1} - 1} ( x + 1 )}) - 1

Schritte zur Lösung

(x y + x) d x + (y x + y) d y = 0

Solve separable ODE:

y = - W (- \frac{1}{e ^{- x + c_{1} - 1} ( x + 1 )}) - 1

y = - W (- \frac{1}{e ^{- x + c_{1} - 1} ( x + 1 )}) - 1

(e^{2 x} + 1) \frac{d y}{d x} = y

y^{^{'}} = e^{3 x} y^{2}

(x^{2} - 1) y^{^{'}} + x y (1 - y) = 0

\frac{d x}{d t} = e^{x} t cos (t)

\frac{d y}{d x} + 9 x^{2} y = 27 x^{2}