+xyedy+4xdx=0

Lösung

+ x ye d y + 4 x d x = 0

y = \frac{- 8 x + c _{1}}{e}, y = - \frac{- 8 x + c _{1}}{e}

Schritte zur Lösung

+ x ye d y + 4 x d x = 0

Solve separable ODE:

y = \frac{- 8 x + c _{1}}{e}, y = - \frac{- 8 x + c _{1}}{e}

y = \frac{- 8 x + c _{1}}{e}, y = - \frac{- 8 x + c _{1}}{e}

y^{^{'}} = - x^{2} y^{2}

\frac{d y}{d x} = 2 x y^{3}

9 x t^{2} = \frac{d x}{d t}

9 t^{2} \frac{d x}{d t} + 8 x + 8 = 0

x^{^{'}} - c x = 0