y^'+18y^'+81y=0

Lösung

y^{^{'}} + 18 y^{^{'}} + 81 y = 0

y = e^{\frac{- 81 t + c _{1}}{19}}

Schritte zur Lösung

y^{'} (t) + 18 y^{'} (t) + 81 y = 0

Solve separable ODE:

y = e^{\frac{- 81 t + c _{1}}{19}}

y = e^{\frac{- 81 t + c _{1}}{19}}

\frac{d y}{d x} = (- n y)

\frac{d h}{d t} = kh (t)^{n}

x + \frac{y d y}{d x} = 2

y + 4 y^{^{'}} + 5 y = 0

(t^{2} + 1) x^{^{'}} = - 3 t x + 6 t