y^'=-(x+2)y^2

Lösung

y^{^{'}} = - (x + 2) y^{2}

y = - \frac{2}{- x ^{2} - 4 x + c _{1}}

Schritte zur Lösung

y^{'} (x) = - (x + 2) y^{2}

Solve separable ODE:

y = - \frac{2}{- x ^{2} - 4 x + c _{1}}

y = - \frac{2}{- x ^{2} - 4 x + c _{1}}

(3 t^{2} + 5) y^{^{'}} = 3 t y, y (0) = 8

\frac{d y}{d x} = \frac{x ^{3}}{y ^{3}}

y^{^{'}} = e^{4 y + 7 t}

\frac{d y}{d x} = - ln ∣ x ∣ y

ln (y^{6}) \frac{d y}{d x} = x^{6} y, y (1) = e^{2}