sin(sin(3x))dx+2y^3xdy=0

解

sin (sin (3 x)) d x + 2 y^{3} x d y = 0

y = 2 4 \int - \frac{sin ( sin ( 3 x ) )}{2 x} d x, y = - 2 4 \int - \frac{sin ( sin ( 3 x ) )}{2 x} d x

解答ステップ

sin (sin (3 x)) d x + 2 y^{3} x d y = 0

分離可能 ODE を解く:

y = 2 4 \int - \frac{sin ( sin ( 3 x ) )}{2 x} d x, y = - 2 4 \int - \frac{sin ( sin ( 3 x ) )}{2 x} d x

y = 2 4 \int - \frac{sin ( sin ( 3 x ) )}{2 x} d x, y = - 2 4 \int - \frac{sin ( sin ( 3 x ) )}{2 x} d x