(dy)/(dt)=ky+an

Lösung

\frac{d y}{d t} = k y + an

y = \frac{e ^{t k + c_{1}}}{k} - \frac{an}{k}

Schritte zur Lösung

\frac{d y}{d t} = k y + an

Solve separable ODE:

y = \frac{e ^{t k + c_{1}}}{k} - \frac{an}{k}

y = \frac{e ^{t k + c_{1}}}{k} - \frac{an}{k}

\frac{d x}{d y} = e^{- y} (2 x - 4)

\frac{d y}{d x} - y x^{2} = - y

(x - 6) y^{^{'}} + y = 0

\frac{d y}{d x} = \frac{x}{y}, y \neq = 0

(π + π y) d x - (e - e x) d y = 0