y^'=10xy-2x,y(0)=7

Lösung

y^{^{'}} = 10 x y - 2 x, y (0) = 7

y = \frac{34 e ^{5 x^{2}}}{5} + \frac{1}{5}

Schritte zur Lösung

y^{'} (x) = 10 x y - 2 x

Solve separable ODE:

y = \frac{34 e ^{5 x^{2}}}{5} + \frac{1}{5}

y = \frac{34 e ^{5 x^{2}}}{5} + \frac{1}{5}

(x^{2} - 1) \frac{d y}{d x} + x y = x

\frac{d x}{d t} = 9 x t^{5}

y^{^{'}} - \frac{t ^{5}}{y} = 0, y (0.3) = 3

\frac{d y}{d x} = b y

\frac{d x}{d y} + 6 e^{y + x} = 0