(y/2)y^'=e^{-x}

Lösung

(\frac{y}{2}) y^{^{'}} = e^{- x}

y = 2 - e^{- x} + c_{1}, y = - 2 - e^{- x} + c_{1}

Schritte zur Lösung

(\frac{y}{2}) y^{'} (x) = e^{- x}

Solve separable ODE:

y = 2 - e^{- x} + c_{1}, y = - 2 - e^{- x} + c_{1}

y = 2 - e^{- x} + c_{1}, y = - 2 - e^{- x} + c_{1}

y^{^{'}} = x y + \frac{4 x}{y}, y (0) = 1

\frac{d x}{d t} = x^{2} t

(x^{2} + 1) y + 2 x y^{^{'}} + (e^{x}) x y = 0

7 t y^{^{'}} + y = 0

x y^{^{'}} \cdot y = x^{2} sin (x)