y^'=10y^{-2},y(0)=3

Lösung

y^{^{'}} = 10 y^{- 2}, y (0) = 3

y = 3 30 t + 27

Schritte zur Lösung

y^{'} (t) = 10 y^{- 2}

Solve separable ODE:

y = 3 30 t + 27

y = 3 30 t + 27

y y^{^{'}} = 4 sin (x)

2500 \cdot \frac{d x}{d y} + 2875 \cdot x = 0, x (0) = 8.5

\frac{d y}{d x} y = 2 ln (3 + x^{2})

t \cdot \frac{d y}{d t} = - y \cdot (1 + 2 t^{2})

y^{^{'}} = 5 x^{2} y + y