y^'=5xy^6

解答

y^{^{'}} = 5 x y^{6}

y = - 5 \frac{2}{5 ( 5 x ^{2} + c _{1} )}

求解步骤

y^{'} (x) = 5 x y^{6}

求解可分离方程:

y = - 5 \frac{2}{5 ( 5 x ^{2} + c _{1} )}

y = - 5 \frac{2}{5 ( 5 x ^{2} + c _{1} )}

7 y d y = \frac{3}{x} d x

x^{2} + 6 d x - \frac{1}{x csc ( - 8 y )} d y = 0

y^{^{'}} = \frac{y ( y - 2 )}{x ( y - 1 )}

x \cdot \frac{d x}{d t} = e^{3 x} t

x^{^{'}} = e^{x} \cdot t \cdot cos (t)