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Beliebt Rechnen >

y^'=(y+5)/(7t+50),y(2)=0

Lösung

y^{^{'}} = \frac{y + 5}{7 t + 50}, y (2) = 0

Lösung

y = \frac{5 7 7 t + 50}{e ^{\frac{6 l n ( 2 )}{7}}} - 5

Schritte zur Lösung

y^{'} (t) = \frac{y + 5}{7 t + 50}

Solve separable ODE:

y = \frac{5 7 7 t + 50}{e ^{\frac{6 l n ( 2 )}{7}}} - 5

y = \frac{5 7 7 t + 50}{e ^{\frac{6 l n ( 2 )}{7}}} - 5

Beliebte Beispiele

(1+x)(dy)/(dx)=e^{-y}-1

(1 + x) \frac{d y}{d x} = e^{- y} - 1

1500/230 (1-30x^')= x/(0.1)+75x^'

\frac{1500}{230} (1 - 30 x^{^{'}}) = \frac{x}{0.1} + 75 x^{^{'}}

y^'+ay+(2*y)/x =0

y^{^{'}} + a y + \frac{2 \cdot y}{x} = 0

(dP)/(dt)=P-P^{-2}

\frac{d P}{d t} = P - P^{- 2}

(dy)/(dx)=y^2-y+2

\frac{d y}{d x} = y^{2} - y + 2