(f(t))=1f^'

Lösung

(f (t)) = 1 f^{^{'}}

f (t) = e^{t + c_{1}}

Schritte zur Lösung

(f (t)) = 1 f^{'} (t)

Solve separable ODE:

f (t) = e^{t + c_{1}}

f (t) = e^{t + c_{1}}

\frac{d y}{d x} = y x^{3} - 1.5 y

\frac{d}{d x} ((y) \cdot 2) = 2 \cdot 10 - 3 y

y^{^{'}} + \frac{y}{4} = 4, y (- 3) = 0

(2 x + 3)^{4} = 3 y^{4} \frac{d y}{d x}

\frac{d y}{d x} = - \frac{4}{6} x^{8} y^{6}