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Beliebt Rechnen >

y^{''}+y^'=cos(x),y(0)=0,y^'(0)=2

Lösung

y^{^{''}} + y^{^{'}} = cos (x), y (0) = 0, y^{^{'}} (0) = 2

Lösung

y = \frac{3}{2} + \frac{1}{2} - \frac{3}{2} e^{- x} + \frac{sin ( x ) - cos ( x )}{2}

Schritte zur Lösung

y^{''} (x) + y^{'} (x) = cos (x)

Solve linear ODE:

y = \frac{3}{2} + \frac{1}{2} - \frac{3}{2} e^{- x} + \frac{sin ( x ) - cos ( x )}{2}

y = \frac{3}{2} + \frac{1}{2} - \frac{3}{2} e^{- x} + \frac{sin ( x ) - cos ( x )}{2}

Graph

Beliebte Beispiele

y^{''}-9y=cosh(3x)

y^{^{''}} - 9 y = cosh (3 x)

y^{''''}-16y=-12t^3

y^{^{''''}} - 16 y = - 12 t^{3}

y^{''}-100y=sinh(10x)

y^{^{''}} - 100 y = sinh (10 x)

14y^{''}+y^'+y=x^2-5x

14 y^{^{''}} + y^{^{'}} + y = x^{2} - 5 x

y^{''}+106y^'+26y=2t^3e^{-5t}sin(t)

y^{^{''}} + 106 y^{^{'}} + 26 y = 2 t^{3} e^{- 5 t} sin (t)