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Beliebt Rechnen >

14y^{''}+y^'+y=x^2-4x

Lösung

14 y^{^{''}} + y^{^{'}} + y = x^{2} - 4 x

Lösung

y = e^{- \frac{x}{28}} (c_{1} cos (\frac{55 x}{28}) + c_{2} sin (\frac{55 x}{28})) + x^{2} - 6 x - 22

Schritte zur Lösung

14 y^{''} (x) + y^{'} (x) + y = x^{2} - 4 x

Solve linear ODE:

y = e^{- \frac{x}{28}} (c_{1} cos (\frac{55 x}{28}) + c_{2} sin (\frac{55 x}{28})) + x^{2} - 6 x - 22

y = e^{- \frac{x}{28}} (c_{1} cos (\frac{55 x}{28}) + c_{2} sin (\frac{55 x}{28})) + x^{2} - 6 x - 22

Graph

Beliebte Beispiele

y^{'''}-y^{''}=cos(2t)

y^{^{'''}} - y^{^{''}} = cos (2 t)

y^{''}-3y^'+2y=2xe^x

y^{^{''}} - 3 y^{^{'}} + 2 y = 2 x e^{x}

y^{''}-2y^'-3y=e^t,y(0)=2,y^'(0)=4

y^{^{''}} - 2 y^{^{'}} - 3 y = e^{t}, y (0) = 2, y^{^{'}} (0) = 4

y^{^{''}} - y = 2 t - 4

y^{'''}-2y^{''}-4y^'+8y=e^{-3x}+8x^2

y^{^{'''}} - 2 y^{^{''}} - 4 y^{^{'}} + 8 y = e^{- 3 x} + 8 x^{2}