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Beliebt Rechnen >

y^{''}+4y^'+5y=e^{-2x}sec(x)

Lösung

y^{^{''}} + 4 y^{^{'}} + 5 y = e^{- 2 x} sec (x)

Lösung

y = e^{- 2 x} (c_{1} cos (x) + c_{2} sin (x)) + ln (cos (x)) e^{- 2 x} cos (x) + x e^{- 2 x} sin (x)

Schritte zur Lösung

y^{''} (x) + 4 y^{'} (x) + 5 y = e^{- 2 x} sec (x)

Solve linear ODE:

y = e^{- 2 x} (c_{1} cos (x) + c_{2} sin (x)) + ln (cos (x)) e^{- 2 x} cos (x) + x e^{- 2 x} sin (x)

y = e^{- 2 x} (c_{1} cos (x) + c_{2} sin (x)) + ln (cos (x)) e^{- 2 x} cos (x) + x e^{- 2 x} sin (x)

Graph

Beliebte Beispiele

y^{''}-5y^'+4y=1

y^{^{''}} - 5 y^{^{'}} + 4 y = 1

y^{''}-100y=9t^2e^{10t}

y^{^{''}} - 100 y = 9 t^{2} e^{10 t}

y^{''}-16y=cosh(4x)

y^{^{''}} - 16 y = cosh (4 x)

y^{''}+9y=(csc(3x))/4

y^{^{''}} + 9 y = \frac{csc ( 3 x )}{4}

y^{''}+9y= 3/2 sin(2t),y(0)=0,y^'(0)=0

y^{^{''}} + 9 y = \frac{3}{2} sin (2 t), y (0) = 0, y^{^{'}} (0) = 0