y^{''}-y^'-2y=3x+2

Lösung

y^{^{''}} - y^{^{'}} - 2 y = 3 x + 2

y = c_{1} e^{2 x} + c_{2} e^{- x} - \frac{3 x}{2} - \frac{1}{4}

Schritte zur Lösung

y^{''} (x) - y^{'} (x) - 2 y = 3 x + 2

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{- x} - \frac{3 x}{2} - \frac{1}{4}

y = c_{1} e^{2 x} + c_{2} e^{- x} - \frac{3 x}{2} - \frac{1}{4}

y^{^{''''}} + 9 y^{^{''}} = cos (3 t)

y^{^{''}} - 2 y^{^{'}} + 5 y = 4 e^{3 t}

y^{^{''}} + y = 1 - H (t - 3 π)

\frac{d ^{2} y}{d t ^{2}} + 4 y = 3 cos (2 t)

y^{^{''}} + 2 y = 3 x