y^{'''}-y^'=11sin(t)

Lösung

y^{^{'''}} - y^{^{'}} = 11 sin (t)

y = c_{1} + c_{2} e^{- t} + c_{3} e^{t} + \frac{11}{2} cos (t)

Schritte zur Lösung

y^{'''} (t) - y^{'} (t) = 11 sin (t)

Solve linear ODE:

y = c_{1} + c_{2} e^{- t} + c_{3} e^{t} + \frac{11}{2} cos (t)

y = c_{1} + c_{2} e^{- t} + c_{3} e^{t} + \frac{11}{2} cos (t)

(D^{2} - D - 2) y = 18 x e^{- x}

y^{^{''}} - 2 y^{^{'}} + y = e^{t}, y (0) = 1, y^{^{'}} (0) = 0

x^{^{''}} + x = 1

x^{^{''}} + x = 5

y^{^{'''}} + y^{^{''}} - 1 = 0