y^{''}-8y^'+7=0

Lösung

y^{^{''}} - 8 y^{^{'}} + 7 = 0

y = c_{1} e^{8 t} + c_{2} + \frac{7 t}{8}

Schritte zur Lösung

y^{''} (t) - 8 y^{'} (t) + 7 = 0

Solve linear ODE:

y = c_{1} e^{8 t} + c_{2} + \frac{7 t}{8}

y = c_{1} e^{8 t} + c_{2} + \frac{7 t}{8}

y^{^{''}} + 8 y^{^{'}} + 7 y = e^{- 2 x}

y^{^{''}} - y^{^{'}} = 2 x - 3

y^{^{''}} - y^{^{'}} = 2 x + 4

y^{^{''}} + 2 y^{^{'}} + 5 = 0

y^{^{''}} + y = 2 e^{3 x}