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Beliebt Rechnen >

y^{''}+4y=32sin(2x)+16cos(2x)

Lösung

y^{^{''}} + 4 y = 32 sin (2 x) + 16 cos (2 x)

Lösung

y = c_{1} cos (2 x) + c_{2} sin (2 x) + 4 x sin (2 x) - 8 x cos (2 x)

Schritte zur Lösung

y^{''} (x) + 4 y = 32 sin (2 x) + 16 cos (2 x)

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x) + 4 x sin (2 x) - 8 x cos (2 x)

y = c_{1} cos (2 x) + c_{2} sin (2 x) + 4 x sin (2 x) - 8 x cos (2 x)

Graph

Beliebte Beispiele

5y^{''}+y^'=-6x,y(0)=0,y^'(0)=-10

5 y^{^{''}} + y^{^{'}} = - 6 x, y (0) = 0, y^{^{'}} (0) = - 10

y^{'''}+y^'=sin(x)

y^{^{'''}} + y^{^{'}} = sin (x)

y^{''}+2y^'+y=(ln(x))/(e^x)

y^{^{''}} + 2 y^{^{'}} + y = \frac{ln ( x )}{e ^{x}}

y^{''}-y^'-2y=((e^{2t}+e^{-2t}))/2

y^{^{''}} - y^{^{'}} - 2 y = \frac{( e ^{2 t} + e ^{- 2 t} )}{2}

(D^3+10D^2+25D)y=e^x

(D^{3} + 10 D^{2} + 25 D) y = e^{x}