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Beliebt Rechnen >

4y^{''}+16y=1,y(0)=-2,y^'(0)=0

Lösung

4 y^{^{''}} + 16 y = 1, y (0) = - 2, y^{^{'}} (0) = 0

Lösung

y = - \frac{33}{16} cos (2 t) + \frac{1}{16}

Schritte zur Lösung

4 y^{''} (t) + 16 y = 1

Solve linear ODE:

y = - \frac{33}{16} cos (2 t) + \frac{1}{16}

y = - \frac{33}{16} cos (2 t) + \frac{1}{16}

Graph

Beliebte Beispiele

y^{^{''}} + y = t^{3}

y^{''}-8y^'+16y=x

y^{^{''}} - 8 y^{^{'}} + 16 y = x

y^{''}-6y^'+9y=e^x

y^{^{''}} - 6 y^{^{'}} + 9 y = e^{x}

y^{''}-10y^'+25y=6t^2e^{5t}

y^{^{''}} - 10 y^{^{'}} + 25 y = 6 t^{2} e^{5 t}

y^{''}-12y^'+36y=18x+2

y^{^{''}} - 12 y^{^{'}} + 36 y = 18 x + 2