y^{''}+36y=11sec^2(6t)

解

y^{^{''}} + 36 y = 11 sec^{2} (6 t)

y = c_{1} cos (6 t) + c_{2} sin (6 t) + \frac{- 11 + 11 ln ( tan ( 6 t ) + sec ( 6 t ) ) sin ( 6 t )}{36}

解答ステップ

y^{''} (t) + 36 y = 11 sec^{2} (6 t)

線形 ODE を解く:

y = c_{1} cos (6 t) + c_{2} sin (6 t) + \frac{- 11 + 11 ln ( tan ( 6 t ) + sec ( 6 t ) ) sin ( 6 t )}{36}

y = c_{1} cos (6 t) + c_{2} sin (6 t) + \frac{- 11 + 11 ln ( tan ( 6 t ) + sec ( 6 t ) ) sin ( 6 t )}{36}