y^{''}+9y=6cos(3x)

解答

y^{^{''}} + 9 y = 6 cos (3 x)

y = c_{1} cos (3 x) + c_{2} sin (3 x) + x sin (3 x)

求解步骤

y^{''} (x) + 9 y = 6 cos (3 x)

求解线性方程:

y = c_{1} cos (3 x) + c_{2} sin (3 x) + x sin (3 x)

y = c_{1} cos (3 x) + c_{2} sin (3 x) + x sin (3 x)

(D^{2} - 3 D + 2) y = e^{3 x}

\frac{5}{6} q^{^{''}} + 10 q^{^{'}} + 60 q = 600

x^{^{''}} + \frac{1.0889}{19.6} x = cos (2 t)

0.001 y^{^{''}} + 10 y = 10 cos (100 x)

y^{^{''}} + 2 y^{^{'}} + y = (1 + x) e^{- x}