y^{''}+4y=e^3x

Lösung

y^{^{''}} + 4 y = e^{3} x

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{e ^{3} x}{4}

Schritte zur Lösung

y^{''} (x) + 4 y = e^{3} x

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{e ^{3} x}{4}

y = c_{1} cos (2 x) + c_{2} sin (2 x) + \frac{e ^{3} x}{4}

x^{^{''}} + 2 x^{^{'}} + x = t

y^{^{''}} - 9 y = - 8 e^{t}

y^{^{'''}} + 3 y^{^{''}} + y^{^{'}} + 3 y = e^{x} + 4

y^{^{''}} + 9 y = cos (2 x)

y^{^{''}} - 10 y^{^{'}} + 25 y = x