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Beliebt Rechnen >

y^{''}+4y=3cos(2t),y(0)=1,y^'(0)=0

Lösung

y^{^{''}} + 4 y = 3 cos (2 t), y (0) = 1, y^{^{'}} (0) = 0

Lösung

y = \frac{3 t sin ( 2 t )}{4} + cos (2 t)

Schritte zur Lösung

y^{''} (t) + 4 y = 3 cos (2 t)

Solve linear ODE:

y = \frac{3 t sin ( 2 t )}{4} + cos (2 t)

y = \frac{3 t sin ( 2 t )}{4} + cos (2 t)

Graph

Beliebte Beispiele

0.125y^{''}+10sqrt(6)y+1000=0

0.125 y^{^{''}} + 106 y + 1000 = 0

y^{''}+y^'=1,y(0)=0,y^'(0)=1

y^{^{''}} + y^{^{'}} = 1, y (0) = 0, y^{^{'}} (0) = 1

y^{''}-4y^'+4y=e^{2x}arctan(x)

y^{^{''}} - 4 y^{^{'}} + 4 y = e^{2 x} arctan (x)

(d^2y)/(dx^2)-5(dy)/(dx)+6y=x^2+x

\frac{d ^{2} y}{d x ^{2}} - 5 \frac{d y}{d x} + 6 y = x^{2} + x

y^{''}-4y^'-12y=-20t+24t^2

y^{^{''}} - 4 y^{^{'}} - 12 y = - 20 t + 24 t^{2}