de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

y^{'''}+y^{''}=2^x

Lösung

y^{^{'''}} + y^{^{''}} = 2^{x}

Lösung

y = c_{1} e^{- x} + c_{2} + c_{3} x + \frac{2 ^{x}}{ln ( 2 e )} - \frac{2 ^{x}}{ln ( 2 )} + \frac{2 ^{x}}{ln ^{2} ( 2 )}

Schritte zur Lösung

y^{'''} (x) + y^{''} (x) = 2^{x}

Solve linear ODE:

y = c_{1} e^{- x} + c_{2} + c_{3} x + \frac{2 ^{x}}{ln ( 2 e )} - \frac{2 ^{x}}{ln ( 2 )} + \frac{2 ^{x}}{ln ^{2} ( 2 )}

y = c_{1} e^{- x} + c_{2} + c_{3} x + \frac{2 ^{x}}{ln ( 2 e )} - \frac{2 ^{x}}{ln ( 2 )} + \frac{2 ^{x}}{ln ^{2} ( 2 )}

Beliebte Beispiele

y^{''}-y^'-y=x^3

y^{^{''}} - y^{^{'}} - y = x^{3}

y^{''}+9y=sin(x)+cos(x)

y^{^{''}} + 9 y = sin (x) + cos (x)

y^{''}+2y^'+y=sec^2(x)

y^{^{''}} + 2 y^{^{'}} + y = sec^{2} (x)

3x^{''}+48x=153e^{-2t}cos(4t)

3 x^{^{''}} + 48 x = 153 e^{- 2 t} cos (4 t)

y^{''}-9y=4e^{3t},y(0)=0,y^'(0)=-1

y^{^{''}} - 9 y = 4 e^{3 t}, y (0) = 0, y^{^{'}} (0) = - 1