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Beliebt Rechnen >

u^{''}+3u^'+5\H(t)=e^{-5t}

Lösung

u^{''} + 3 u^{'} + 5 H (t (x)) = e^{- 5 t (x)}

Lösung

0 + 3 \cdot 0 + 5 H (t (x)) = e^{- 5 t (x)}

Schritte zur Lösung

u^{''} + 3 u^{'} + 5 H (t (x)) = e^{- 5 t (x)}

u^{''} = 0

0 + 3 u^{^{'}} + 5 H (t (x)) = e^{- 5 t (x)}

u^{'} = 0

0 + 3 \cdot 0 + 5 H (t (x)) = e^{- 5 t (x)}

Beliebte Beispiele

y^{''}-4y^'=3e^{2x},y(0)=0,y^'(0)=0

y^{^{''}} - 4 y^{^{'}} = 3 e^{2 x}, y (0) = 0, y^{^{'}} (0) = 0

2y^{''}+50y=2cos(5x)cos(5x)

2 y^{^{''}} + 50 y = 2 cos (5 x) cos (5 x)

(d^2y)/(dt^2)+y=t^2

\frac{d ^{2} y}{d t ^{2}} + y = t^{2}

y^{''}+2y^'+2y=sec(x)e^{-x}

y^{^{''}} + 2 y^{^{'}} + 2 y = sec (x) e^{- x}

y^{''}+4y^'+4y=(e^{(-2x)})/(x^3)

y^{^{''}} + 4 y^{^{'}} + 4 y = \frac{e ^{(- 2 x)}}{x ^{3}}