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Beliebt Rechnen >

30y^{''}+25y^'+4y=40

Lösung

30 y^{^{''}} + 25 y^{^{'}} + 4 y = 40

Lösung

y = c_{1} e^{\frac{( - 25 + 145 ) t}{60}} + c_{2} e^{\frac{( - 25 - 145 ) t}{60}} + 10

Schritte zur Lösung

30 y^{''} (t) + 25 y^{'} (t) + 4 y = 40

Solve linear ODE:

y = c_{1} e^{\frac{( - 25 + 145 ) t}{60}} + c_{2} e^{\frac{( - 25 - 145 ) t}{60}} + 10

y = c_{1} e^{\frac{( - 25 + 145 ) t}{60}} + c_{2} e^{\frac{( - 25 - 145 ) t}{60}} + 10

Graph

Beliebte Beispiele

y^{''}-y=sec^3(x)-sec(x)

y^{^{''}} - y = sec^{3} (x) - sec (x)

y^{''''}-5y^{''}+4y=8cos(2x)-12e^{-x}

y^{^{''''}} - 5 y^{^{''}} + 4 y = 8 cos (2 x) - 12 e^{- x}

x^{''}+x=9cos(8t)

x^{^{''}} + x = 9 cos (8 t)

y^{''}+y=-sec(x)

y^{^{''}} + y = - sec (x)

y^{''}+(sqrt(53))/7*y^'+49x=0

y^{^{''}} + \frac{53}{7} \cdot y^{^{'}} + 49 x = 0