3y^{''}-5y^'=0

Lösung

3 y^{^{''}} - 5 y^{^{'}} = 0

y = c_{1} e^{\frac{5 t}{3}} + c_{2}

Schritte zur Lösung

3 y^{''} (t) - 5 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} e^{\frac{5 t}{3}} + c_{2}

y = c_{1} e^{\frac{5 t}{3}} + c_{2}

y^{^{''}} - 2 y^{^{'}} + 2 y = 0, y (π) = e^{π}, y^{^{'}} (π) = 0

y^{^{'''}} - 9 y^{^{''}} + 23 y^{^{'}} - 15 y = 0

y^{^{''}} + y^{^{'}} - 2 y = 0, y (0) = 1, y^{^{'}} (0) = 4

6 y^{^{''}} - 5 y^{^{'}} + y = 0, y (0) = 4, y^{^{'}} (0) = 0

6 y^{^{''}} + y^{^{'}} - 5 y = 0