(D^2+4)y=0

Lösung

(D^{2} + 4) y = 0

y = c_{1} cos (2 x) + c_{2} sin (2 x)

Schritte zur Lösung

(D^{2} + 4) y = 0

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x)

y = c_{1} cos (2 x) + c_{2} sin (2 x)

x^{^{''}} + x^{^{'}} + 3 x = 0, x (0) = 1, x^{^{'}} (0) = 2

y^{^{''''}} - 8 y^{^{'''}} = 0

y^{^{'''}} - 2 y^{^{''}} + 5 y^{^{'}} = 0

4 y^{^{''}} - 5 y^{^{'}} + y = 0, y (0) = 4, y^{^{'}} (0) = \frac{1}{4}

2 y^{^{''}} + 10 y^{^{'}} + 8 y = 0, y (0) = 5, y^{^{'}} (0) = 0