18y^{''}+72y=0

Lösung

18 y^{^{''}} + 72 y = 0

y = c_{1} cos (2 t) + c_{2} sin (2 t)

Schritte zur Lösung

18 y^{''} (t) + 72 y = 0

Solve linear ODE:

y = c_{1} cos (2 t) + c_{2} sin (2 t)

y = c_{1} cos (2 t) + c_{2} sin (2 t)

10 x^{^{''}} + \frac{1}{90} x = 0, x (0) = 100, x^{^{'}} (0) = 25

\frac{d ^{2} y}{d x ^{2}} + 6 \frac{d y}{d x} + 8 y = 0

y^{^{''''}} - 2 y^{^{'''}} + 4 y^{^{''}} + 2 y^{^{'}} - 5 y = 0

y^{^{''}} - 6 y^{^{'}} + 25 y = 0, y (0) = 2

4 y^{^{''}} + 20 y^{^{'}} + 25 y = 0, y (0) = 1, y^{^{'}} (0) = 2