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Beliebt Rechnen >

4y^{''}+4y^'+6y=0

Lösung

4 y^{^{''}} + 4 y^{^{'}} + 6 y = 0

Lösung

y = e^{- \frac{t}{2}} (c_{1} cos (\frac{5 t}{2}) + c_{2} sin (\frac{5 t}{2}))

Schritte zur Lösung

4 y^{''} (t) + 4 y^{'} (t) + 6 y = 0

Solve linear ODE:

y = e^{- \frac{t}{2}} (c_{1} cos (\frac{5 t}{2}) + c_{2} sin (\frac{5 t}{2}))

y = e^{- \frac{t}{2}} (c_{1} cos (\frac{5 t}{2}) + c_{2} sin (\frac{5 t}{2}))

Graph

Beliebte Beispiele

(d^2y)/(dx^2)-12(dy)/(dx)+35y=0

\frac{d ^{2} y}{d x ^{2}} - 12 \frac{d y}{d x} + 35 y = 0

y^{''}+y^'+3.25y=0

y^{^{''}} + y^{^{'}} + 3.25 y = 0

y^{''}-(2a-1)y^'+a(a-1)y=0

y^{^{''}} - (2 a - 1) y^{^{'}} + a (a - 1) y = 0

y^{''}-4y^'+4y=0,y^'(0)=-2

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y^{^{'}} (0) = - 2

2y^{''}+2y^'+2y=0

2 y^{^{''}} + 2 y^{^{'}} + 2 y = 0