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Beliebt Rechnen >

y^{''}-10y^'+25y=0,y^'(0)=8

Lösung

y^{^{''}} - 10 y^{^{'}} + 25 y = 0, y^{^{'}} (0) = 8

Lösung

y = \frac{e ^{5 t} ( 8 - c _{2} )}{5} + c_{2} e^{5 t} t

Schritte zur Lösung

y^{''} (t) - 10 y^{'} (t) + 25 y = 0

Solve linear ODE:

y = \frac{e ^{5 t} ( 8 - c _{2} )}{5} + c_{2} e^{5 t} t

y = \frac{e ^{5 t} ( 8 - c _{2} )}{5} + c_{2} e^{5 t} t

Graph

Beliebte Beispiele

y^{''}+2y^'+y=0,y(0)=0,y^'(1)=0

y^{^{''}} + 2 y^{^{'}} + y = 0, y (0) = 0, y^{^{'}} (1) = 0

y^{''}+5y^'+14y=0

y^{^{''}} + 5 y^{^{'}} + 14 y = 0

2x^{''}+8x^'+52x=0

2 x^{^{''}} + 8 x^{^{'}} + 52 x = 0

y^{'''}+4y^{''}-7y^'-10y=0

y^{^{'''}} + 4 y^{^{''}} - 7 y^{^{'}} - 10 y = 0

y^{''}+8y^'+16y=0,y(0)=5,y^'(0)=0

y^{^{''}} + 8 y^{^{'}} + 16 y = 0, y (0) = 5, y^{^{'}} (0) = 0