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Beliebt Rechnen >

y^{''}+2y^'+y=0,y(1)=6

Lösung

y^{^{''}} + 2 y^{^{'}} + y = 0, y (1) = 6

Lösung

y = (6 e - c_{2}) e^{- t} + c_{2} t e^{- t}

Schritte zur Lösung

y^{''} (t) + 2 y^{'} (t) + y = 0

Solve linear ODE:

y = (6 e - c_{2}) e^{- t} + c_{2} t e^{- t}

y = (6 e - c_{2}) e^{- t} + c_{2} t e^{- t}

Graph

Beliebte Beispiele

y^{''''}+7y^{'''}+14y^{''}-22y^'-84y=0

y^{^{''''}} + 7 y^{^{'''}} + 14 y^{^{''}} - 22 y^{^{'}} - 84 y = 0

(6 d^{3} + 5 d^{2}) y = 0

(d^4y)/(dt^4)+2y^{''}+y=0

\frac{d ^{4} y}{d t ^{4}} + 2 y^{^{''}} + y = 0

y^{''}=4y,y(0)=1,y(1)=0

y^{^{''}} = 4 y, y (0) = 1, y (1) = 0

y^{''}+36y=0,y(0)=cos(6x)

y^{^{''}} + 36 y = 0, y (0) = cos (6 x)