2y-3y^{''}=0

Lösung

2 y - 3 y^{^{''}} = 0

y = c_{1} e^{\frac{2}{3} t} + c_{2} e^{- \frac{2}{3} t}

Schritte zur Lösung

2 y - 3 y^{''} (t) = 0

Solve linear ODE:

y = c_{1} e^{\frac{2}{3} t} + c_{2} e^{- \frac{2}{3} t}

y = c_{1} e^{\frac{2}{3} t} + c_{2} e^{- \frac{2}{3} t}

y^{^{''}} + 4 y^{^{'}} - 7 y = 0

y^{^{'''}} - 5 y^{^{''}} + 17 y - 13 y = 0

(D^{3} - 4 D^{2} + 5 D) y = 0

4 y^{^{''''}} - 5 y^{^{''}} - 9 y = 0

y^{^{'''}} - 3 y^{^{''}} - 34 y^{^{'}} - 48 y = 0