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Beliebt Rechnen >

y^{''}-25y=0,y(0)=1,y^'(0)=3

Lösung

y^{^{''}} - 25 y = 0, y (0) = 1, y^{^{'}} (0) = 3

Lösung

y = (1 - \frac{1}{5}) e^{5 t} + \frac{1}{5} e^{- 5 t}

Schritte zur Lösung

y^{''} (t) - 25 y = 0

Solve linear ODE:

y = (1 - \frac{1}{5}) e^{5 t} + \frac{1}{5} e^{- 5 t}

y = (1 - \frac{1}{5}) e^{5 t} + \frac{1}{5} e^{- 5 t}

Graph

Beliebte Beispiele

y^{''}+25y=0,y(pi/(10))=-3,y(pi)=-8

y^{^{''}} + 25 y = 0, y (\frac{π}{10}) = - 3, y (π) = - 8

(d^3y)/(dx^3)-5y=0

\frac{d ^{3} y}{d x ^{3}} - 5 y = 0

2y^{''}+(a-1)y=0

2 y^{^{''}} + (a - 1) y = 0

(d^2f)/(dx^2)-f(x)=0

\frac{d ^{2} f}{d x ^{2}} - f (x) = 0

D^2(D-3)^2(D^2+2D+5)y=0

D^{2} (D - 3)^{2} (D^{2} + 2 D + 5) y = 0