x^{''}+cx=0

Lösung

x^{^{''}} + c x = 0

x = c_{1} cos (c t) + c_{2} sin (c t)

Schritte zur Lösung

x^{''} (t) + c x = 0

Solve linear ODE:

x = c_{1} cos (c t) + c_{2} sin (c t)

x = c_{1} cos (c t) + c_{2} sin (c t)

y^{^{''}} - 2 y^{^{'}} = 0, y (0) = 1, y (1) = 0

y^{^{''}} + 4 y^{^{'}} + 4 y = 0, y (0) = 4, y^{^{'}} (0) = - 6

y^{^{''}} - 10 y^{^{'}} + 25 y = 0, y (0) = 1, y^{^{'}} (0) = 0

y^{^{''}} + y^{^{'}} - 6 y = 0, y (1) = 2 e^{2} - e^{- 3}

(D^{3} - 3 D^{2} + 3 D - 1) y = 0