3y^{''}-16y^'+13y=0

Lösung

3 y^{^{''}} - 16 y^{^{'}} + 13 y = 0

y = c_{1} e^{\frac{13 t}{3}} + c_{2} e^{t}

Schritte zur Lösung

3 y^{''} (t) - 16 y^{'} (t) + 13 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{13 t}{3}} + c_{2} e^{t}

y = c_{1} e^{\frac{13 t}{3}} + c_{2} e^{t}

y^{^{''}} + n^{2} y = 0, y (0) = c, y^{^{'}} (0) = v

4 y^{^{''}} - 8 y^{^{'}} + 3 y = 0, y (0) = 2, y^{^{'}} (0) = \frac{1}{2}

f^{^{''}} (t) - f^{^{'}} (t) - 2 f (t) = 0, f (0) = 1, f^{^{'}} (0) = 0

9 y^{^{''}} - 12 y^{^{'}} + 4 y = 0, y (0) = 2, y^{^{'}} (0) = 1

\frac{d ^{2} y}{d x ^{2}} - 10 \frac{d y}{d x} + 29 y = 0