9y^{''}-12y^'+11y=0

Lösung

9 y^{^{''}} - 12 y^{^{'}} + 11 y = 0

y = e^{\frac{2 t}{3}} (c_{1} cos (\frac{7 t}{3}) + c_{2} sin (\frac{7 t}{3}))

Schritte zur Lösung

9 y^{''} (t) - 12 y^{'} (t) + 11 y = 0

Solve linear ODE:

y = e^{\frac{2 t}{3}} (c_{1} cos (\frac{7 t}{3}) + c_{2} sin (\frac{7 t}{3}))

y = e^{\frac{2 t}{3}} (c_{1} cos (\frac{7 t}{3}) + c_{2} sin (\frac{7 t}{3}))

y^{^{''}} + 12 y^{^{'}} + 36 y = 0, y (- 1) = 5, y^{^{'}} (- 1) = 3

4 y^{^{''}} - 19 y^{^{'}} + 12 y = 0, y (0) = 5, y^{^{'}} (0) = 13.5

y^{^{''}} = 6 y^{^{'}} - 8 y, y^{^{'}} (0) = 2

y^{^{''}} - 6 y^{^{'}} + 13 y = 0, y (0) = - 3

5 y^{^{''}} + 45 y = 0, y (0) = - 8, y^{^{'}} (0) = 0