y^{'''}-7y^{''}+25y^'-39y=0

Lösung

y^{^{'''}} - 7 y^{^{''}} + 25 y^{^{'}} - 39 y = 0

y = c_{1} e^{3 t} + e^{2 t} (c_{2} cos (3 t) + c_{3} sin (3 t))

Schritte zur Lösung

y^{'''} (t) - 7 y^{''} (t) + 25 y^{'} (t) - 39 y = 0

Solve linear ODE:

y = c_{1} e^{3 t} + e^{2 t} (c_{2} cos (3 t) + c_{3} sin (3 t))

y = c_{1} e^{3 t} + e^{2 t} (c_{2} cos (3 t) + c_{3} sin (3 t))

y^{^{''}} - 4 y^{^{'}} + 3 y = 0, y (0) = 0, y^{^{'}} (0) = 1

x^{^{''}} + 16.33 x = 0

y^{^{''}} - 18 y^{^{'}} + 81 y = 0, y (0) = 1, y (1) = 0

y^{^{''}} + \frac{a}{4} y = 0, y^{^{'}} (π) = 0, y^{^{'}} (0) = 0

x^{^{''}} + 2 x^{^{'}} + 10 x = 0, x (0) = 1, x^{^{'}} (0) = 0