28y^{''}+17y^'-3y=0

Lösung

28 y^{^{''}} + 17 y^{^{'}} - 3 y = 0

y = c_{1} e^{\frac{t}{7}} + c_{2} e^{- \frac{3 t}{4}}

Schritte zur Lösung

28 y^{''} (t) + 17 y^{'} (t) - 3 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{t}{7}} + c_{2} e^{- \frac{3 t}{4}}

y = c_{1} e^{\frac{t}{7}} + c_{2} e^{- \frac{3 t}{4}}

x^{^{''}} + 6 x^{^{'}} + 25 x = 0, x (0) = \frac{1}{2}, x^{^{'}} (0) = 0

81 y^{^{''}} - 90 y^{^{'}} + 106 y = 0

y^{^{''}} + 4 y^{^{'}} + 13 y = 0, y (0) = 4, y^{^{'}} (0) = - 7

y^{^{''}} - 2 y^{^{'}} + y = 0, y (2) = 1, y^{^{'}} (2) = 2

y^{^{''}} + 14 y^{^{'}} + 51 y = 0