15y^{''''}+92y^{''}+64y=0

Lösung

15 y^{^{''''}} + 92 y^{^{''}} + 64 y = 0

y = c_{1} cos (\frac{2 t}{5}) + c_{2} sin (\frac{2 t}{5}) + c_{3} cos (\frac{4 t}{3}) + c_{4} sin (\frac{4 t}{3})

Schritte zur Lösung

15 y^{(4)} (t) + 92 y^{''} (t) + 64 y = 0

Solve linear ODE:

y = c_{1} cos (\frac{2 t}{5}) + c_{2} sin (\frac{2 t}{5}) + c_{3} cos (\frac{4 t}{3}) + c_{4} sin (\frac{4 t}{3})

y = c_{1} cos (\frac{2 t}{5}) + c_{2} sin (\frac{2 t}{5}) + c_{3} cos (\frac{4 t}{3}) + c_{4} sin (\frac{4 t}{3})

y^{^{''}} + 11 y^{^{'}} + 24 y = 0, y (0) = 1, y^{^{'}} (0) = - 11

10 y^{^{''}} + 9 y^{^{'}} + 2 y = 0, y (0) = 0, y^{^{'}} (0) = 5

10 y^{^{''}} + 9 y^{^{'}} + 2 y = 0, y (0) = 0, y^{^{'}} (0) = 3

(1) y^{^{''}} + (8) y^{^{'}} - (7) y = 0

4 y^{^{''}} + 4 y^{^{'}} + 17 y = 0, y (0) = - 1, y^{^{'}} (0) = - 2